Elizabeth Staniforth b. 26 December 1619

Full Tree
Descendants (Inventory)
Register(s) of the surname

Events

26 December 1619 birth: Eckington (Derbyshire), England

From grandparents to grandchildren

Grandparents

♂ Ralph Staniforth

birth: 1557, Eckington (Derbyshire), England

♀ Dorothy Staniforth

birth: 1558, Eckington (Derbyshire), England

♀ Elizabeth Staniforth

birth: 5 December 1559, Eckington (Derbyshire), England

♂ John Staniforth

birth: 14 March 1560, Eckington (Derbyshire), England

♂ William Staniforth

birth: 27 March 1563, Eckington (Derbyshire), England

♂ Robert Staniforth

birth: 31 August 1567, Eckington (Derbyshire), England

♀ Agnes Staniforth

birth: 31 May 1570, Eckington (Derbyshire), England

♂ Thomas Staniforth

birth: 1556
marriage: ♀ Margaret Scotte , Eckington (Derbyshire), England

♀ Margaret Scotte

birth: 1564, Eckington (Derbyshire), England
marriage: ♂ Thomas Staniforth , Eckington (Derbyshire), England

Grandparents

Parents

♀ Grace Staniforth

birth: 8 October 1587, Eckington (Derbyshire), England

♀ Ann Staniforth

birth: 5 March 1589, Eckington (Derbyshire), England

♀ Jane Staniforth

birth: 5 March 1589, Eckington (Derbyshire), England

♂ Thomas Staniforth

birth: 7 March 1593, Eckington (Derbyshire), England
marriage: ♀ Anne

♀ Anne

marriage: ♂ Thomas Staniforth

Parents

 

== 3 ==

♂ George Staniforth

birth: 27 November 1625, Eckington (Derbyshire), England
marriage: ♀ Dorothy

♀ Anne Staniforth

birth: 2 June 1618, Eckington (Derbyshire), England

♀ Mary Staniforth

birth: 11 November 1621, Eckington (Derbyshire), England

♀ Troth Staniforth

birth: 1627, Eckington (Derbyshire), England

♀ Anne Staniforth

birth: 8 June 1628, Eckington (Derbyshire), England

♀ Jane Staniforth

birth: 27 July 1629, Eckington (Derbyshire), England

♀ Margaret Staniforth

birth: 29 August 1630, Eckington (Derbyshire), England

♀ Jane Staniforth

birth: 25 August 1633, Eckington (Derbyshire), England

♀ Elizabeth Staniforth

birth: 26 December 1619, Eckington (Derbyshire), England

== 3 ==

Scotte

Staniforth